Answer:
[tex]\boxed {\boxed {\sf 74}}[/tex]
Step-by-step explanation:
The nth term of an arithmetic sequence can be found using the following formula.
[tex]a_n=a_1+(n-1)d[/tex]
Where n is the term, a₁ is the first term, and d is the common difference.
We want to find the 21st term, we know the first term is -6, and the common difference is 4.
[tex]n= 21\\a_1= -6 \\d=4[/tex]
Substitute the values into the formula.
[tex]a_{21}=-6+(21-1)4[/tex]
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
Solve inside the parentheses.
[tex]a_{21}=-6+(20)4[/tex]
Multiply 20 and 4.
[tex]a_{21}= -6+80 \\[/tex]
Add -6 and 80.
[tex]a_{21}=74[/tex]
The 21st term of the sequence is 74
Answer:
Here we will use the formula
[tex] \tt \: a_n \: = a_1 +( n - 1)\: \times d[/tex]
[tex] \tt\: a_{21} = −6+(21−1)4[/tex]
By using PEMDAS
[tex] \tt \: a_{21} = - 6 + (20)4[/tex]
[tex] \tt \: a_{21} \: = - 6 + 80 = 74[/tex]
[tex] \huge \tt \bigodot \: \: 74[/tex]
