Question

find the distance from the point (6,10) to the line y=-x to the nearest tenth

Answer 1

points (6,10)
y = -x
x + y = 0

distance = lax1 + by1 + cl/√(a^2 + b^2)
 = l1(6) + 1(10) + 0l/√(1^2 + 1^2)
 = l6 + 10 + 0l/√(1 + 1)
 = l16l/√2
 = 16/√2
 = 8 .2/√2
 = 8 . √2.√2/√2
= 8√2