keiryflores keiryflores

20-10-2016
Mathematics

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An architect is determining the rectangular dimensions of a room. The length measures 6 more than the width. The height is 8 feet less than the length. The sum of all three measures is 46. What are the measurements of the room?

Respuesta :

20-10-2016

first you multiply 6*8 which is the length and the height and you 48. Then you divide by 2 and you get 24 as the width.

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