Question

a shot putter heaves a 7.26kg shot with final velocity of 7.50m/s what is kinetic energy?

Answer 1

Answer: KE=.5mv^2

KE=.5(7.62)(7.5)^2

KE=.5(7.62)(56.25)

KE=.5(428.625)

KE=214.3125 J of KE

Explanation:

Answer 2

The Kinetic energy will be "214.32 J".

Given:

• Mass, m = 7.26 kg
• Final velocity, v = 7.50 m/s

As we know,

→ $K.E = \frac{1}{2} mv^2$

By substituting the values, we get

          $= \frac{1}{2}\times 762\times (7.5)^2$

          $= \frac{1}{2}\times 7.62\times 56.25$

          $= \frac{1}{2}\times 428.625$

          $= 214.32 \ J$

Thus the response above is appropriate.

Learn more about Kinetic energy here:

https://brainly.com/question/1320807