A frog jumps ( 3/5 feet in the span of 2 2/3 seconds. Find the unit rate, in feet per second, that the frog is moving at. Express any improper fractions as mixed numbers.

Respuesta :

Answer: [tex]4\dfrac{4}{9}\text{ feet per second}[/tex]

Step-by-step explanation:

Given: A frog jumps [tex]\dfrac35[/tex] feet in the span of [tex]2\dfrac23[/tex] seconds.

So, distance = [tex]\dfrac35[/tex] feet , time = [tex]2\dfrac23[/tex] seconds = [tex]\dfrac83[/tex] seconds.

Unit rate of movement = [tex]\dfrac{\dfrac83}{\dfrac35}\text{ feet per second}[/tex]

[tex]=\dfrac{40}{9}\text{ feet per second}\\\\=4\dfrac{4}{9}\text{ feet per second}[/tex]

Unit rate=    [tex]4\dfrac{4}{9}\text{ feet per second}[/tex]