Answer:
p1 = 70 deer
p2 = 98 deer
Step-by-step explanation:
We use the population growth expression:
[tex]N(t)=N_0\,(1+r)^t[/tex]
which in our case renders:
[tex]N(t)=N_0\,(1+r)^t\\N(t)=50\,(1+0.4) ^t\\N(t)=50\,(1.4) ^t[/tex]
Therefore, after 1 year the population would be:
[tex]N(1)=50\,(1.4) ^1=70[/tex]
giving a total of 70 deer
and after two years, it would be:
[tex]N(2)=50\,(1.4) ^2=98[/tex]