find the length of the indicated triangle
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Answer:
[tex]35\ units[/tex]
Step-by-step explanation:
[tex]We\ are\ given\ that,\\Side\ JK=(4x+19)\\Side\ KL=(9x-1)\\Now, By\ observing\ the\ triangle, we\ notice\ that\ \angle K = \angle L = \angle J.\\ Hence,\triangle JKL\ is\ an\ equilateral\ triangle\ as\ all\ its\ angles\ are\ equal.\\Hence,\\Another\ property\ of\ an\ equilateral\ triangle\ is\ its\ sides\ are\ equal\ too.\\Hence,\\Side\ JK= Side\ KL= Side\ JL\\Hence,\\By\ focusing\ only\ over\ the\ Sides\ JK\ and KL,\\(4x+19)=(9x-1)\\Hence,\\By\ solving\ the\ equation,\\4x+19=9x-1\\[/tex]
[tex]19+1=9x-4x\\By\ using\ the\ Symmetric\ Property\ Of\ Equation,\\9x-4x=19+1\\Hence,\\5x=20\\x=4\\Now,\\As\ KL=(9x-1)\\By\ substituting\ x=4\ in\ (9x-1) ,\\9*4-1\\=36-1\\=35[/tex]