Question

If the width of a rectangle is 9 ft less then twice it’s length and the perimeter is 30 feet, what are the dimensions of the rectangle?

Answer 1

9 times 30, and the other number would be 18 :))

Answer 2

The dimension of the rectangle is,

The length of the rectangle is 7 feet.

And the width of the rectangle is 8 feet.

Given that,

If the width of a rectangle is 9 ft less than twice its length and the perimeter is 30 feet,

We have to determine,

What are the dimensions of the rectangle?

According to the question,

Let, the width of the rectangle is W,

And the length of a rectangle is L = 2W - 9,

The perimeter of the rectangle is = 2(L+W)

Where perimeter is 30 feet,

Therefore,

$30 = 2(2W-9+W)\\\\30 = 2(3W-9)\\\\30 = 6W-18\\\\30 + 18 = 12W\\\\48 = 6W\\\\W = \dfrac{48}{6}\\\\W = 8 \ feet$

And the length of a rectangle is,

$L = 2W - 9, \\\\L= 2(8) - 9\\\\L = 16-9 \\\\L =7 \ feet.$

Hence, The dimension of the rectangle is, the length of the rectangle is 7 feet, and the width of the rectangle is 8 feet.

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