In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of MN, MO, and JK?

Respuesta :

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

L is the mid-point of ON

J is the mid-point of MO

K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

JL = [tex]\frac{1}{2}[/tex] MN

JL = 11 units

∴ 11 = [tex]\frac{1}{2}[/tex] MN

→ Multiply both sides by 2

∴ 22 = MN

MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

KL = [tex]\frac{1}{2}[/tex] MO

KL = 13 units

∴ 13 = [tex]\frac{1}{2}[/tex] MO

→ Multiply both sides by 2

∴ 26 = MO

MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

JK = [tex]\frac{1}{2}[/tex] ON

ON =20 units

∴ JK = [tex]\frac{1}{2}[/tex] (20)

JK = 10 units

The lengths of MN are 22 units, MO is 26 units and JK is 10 units