Answer:
The new electric field strength is 2E
Explanation:
The electric field between parallel plated can be calculated from the formula
E = V/d
Where E is the Electric field strength
V is the potential difference between the plates
and d is the separation between them
In the first instance where the electric field strength between the parallel plates is E. Let the potential difference (V) be V₁ and the separation between the plates (d) be d₁.
∴ E = V₁/d₁
Now, from the question
The separation of plate is doubled, that is, d = 2d₁
and potential difference between the plate is increased by factor of 4, that is, V = 4V₁
Then,
From E = V/d
Let the new electric field be E₂
Then,
E₂ = 4V₁/2d₁ = 2V₁/d₁
E₂ = 2(V₁/d₁)
E₂ = 2E
Hence, the new electric field strength is 2E.