Solve by using elimination. Express your answer as an ordered pair.
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Answer:
(-2, 0)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Equality Properties
Algebra I
Step-by-step explanation:
Step 1: Define Systems
-x - 2y = 2
4x - 2y = -8
Step 2: Rewrite Systems
-x - 2y = 2
Step 3: Redefine Systems
x + 2y = -2
4x - 2y = -8
Step 4: Solve for x
Elimination
Step 5: Solve for y
Greetings again.
The answer is (-2,0)
Explanation:
This one is different from other 2 previous questions. The last and previous 2 questions have positive y for another equation and negative y for another equation which makes them 0 (As y - y = 0)
But this one is different. y-terms both are negative for both equations. If we decide to add -2y and -2y then It'd make -4y which doesn't make 0.
And how are we gonna solve by elimination? That's simple. By multiplying one of the equation by -1.
We can do that, to eliminate y-term out. Choose one equation to multiply. I'll be multiplying -1 in the first equation.
[tex]-x-2y=2[/tex]
Multiply -1 in whole equation.
[tex]-x(-1)-2y(-1)=2(-1)\\x+2y=-2[/tex]
Remind that negative multiply/distribute in negative equal positive always.
And x + 2y = -2 is your new equation from the first equation.
[tex]\left \{ {{x+2y=-2} \atop {4x-2y=-8}} \right.[/tex]
This is our new equations. Then we are able to eliminate y-term.
[tex]5x=-10\\x=-2[/tex]
In case if you forget again, we can simply add/subtract vertically.
x+4x = 5x
2y-2y = 0
-2-8 = -10
That's how we get 5x=-10 and thus x = -2.
We already get x-value, and you know that we need to find the y-value too.
Therefore, substitute x = -2 in any given equations. Less coefficient value, the faster and better.
I'll substitute in -x-2y=2
[tex]-x-2y=2[/tex]
Substitute x = -2 in the equation.
[tex]-(-2)-2y=2\\2-2y=2\\-2y=2-2\\-2y=0\\y=\frac{0}{-2}\\y=0[/tex]
Thus, when x = -2, y = 0. Since you want the answer as ordered pair, then the answer is (-2,0)