Question

A cylindrical container is filled with oil to a depth of 32 cm if the pressure exerted at the base of the container is known to be. 2560pa then how much is the density if the oil?

Answer 1

Answer:

Ro = 815 [kg/m³]

Explanation:

The static pressure of any fluid can be calculated by means of the following expression.

$P=Ro*g*h$

where:

Ro = density [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = depth [m]

P = pressure [Pa]

Now we can calculate the depth

$2560=Ro*9.81*(32/100)\\Ro=815 [kg/m^{3} ]$

Answer 2

The static pressure of the fluid can be calculated by the formula. The dencity of the given oil is 815 kg/m3.

The static pressure of the fluid can be calculated by the formula,  

P = Ro g h

Where,  

Ro = density [kg/m³] =?  

g = gravity acceleration = 9.81 m/s²  

h = depth = 32 cm = 0.32 m  

P = pressure = 2560 pa

 

put the values in the formula,  

2560 = Ro x 9.18 x 0.32

Ro = 815 kg/m3

Therefore, the dencity of the given oil is 815 kg/m3.

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