Question

A cylindrical container is filled with oil to a depth of 32cm. If the pressure exerted at the base of the container is known to be 2560pa then, how much is the density of the oil?

Answer 1

Answer:

Ro = 815.5 [kg/m³]

Explanation:

We must use the following equation to find the hydrostatic pressure exerted on the bottom of the cylinder.

$P=Ro*g*h$

where:

P = pressure = 2560 [Pa]

Ro = density [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 32 [cm] = 0.32 [m]

$2560=Ro*9.81*0.32\\Ro=815.5 [kg/m^{3} ]$

Answer 2

Answer:

800kg/m^3

Explanation:

roh=2560/0.32m×10m/s^2

800kg/m^3

Change 32 cm to m to make it more easier.

Gravitational acceleration is 10m/s^2.

HOPE THAT I HELPED YOU!