Question

Question 6 (1 point)
Given the following equations, what is (fog)(-6)?
f(x) = 3x² – 15
g(x) =1-
2
Оа
57
Ob
60
Oc
-61
Od
-48
Next Page
Back
Review Answers

Answer 1

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as g(x) is not properly written.

I'll assume the following:

$f(x) = 3x^2 - 15$

$g(x) = 1- 2x$

Required

Determine (f o g)(-6)

In functions:

(f o g)x = f(g(x))

So:

$(f o g)(-6) = f(g(-6))$

First, we calculate g(-6)

$g(x) = 1- 2x$

$g(-6) = 1 - 2*-6$

$g(-6) = 13$

Substitute 13 for g(-6) in $(f o g)(-6) = f(g(-6))$

$(f o g)(-6) = f(13)$

Next, we calculate f(13)

$f(x) = 3x^2 - 15$

$f(13) = 3 * 13^2 - 15$

$f(13) = 3 * 169 - 15$

$f(13) = 492$

Hence:

$(f o g)(-6) = 492$

Use the above analysis and explanation to answer your question