Question

One number is four more than a second number. Two times the first number is 8 more than four times the second number.

Answer 1

Answer:

The required numbers are:

First number = 4

Second number = 0

Step-by-step explanation:

Let First number = x

second number = y

We are given:

One number is four more than a second number.

Writing in mathematical form:

$x=y+4$

Two times the first number is 8 more than four times the second

Writing in mathematical form:

$2x=4y+8$

Now, we will solve these equations by substitution to find values of x and y

Let:

$x=y+4--eq(1)\\2x=4y+8--eq(2)$

Now, putting value of x from eq(1) into eq(2)

$2x=4y+8\\Put\:x= y+4\\2(y+4)=4y+8\\2y+8=4y+8\\2y-4y=8-8\\-2y=0\\y=0$

So, we get y=0

Now put value of y in equation 1 to get value of x

$x=y+4\\x=0+4\\x=4$

So, we get x=4

So, the required numbers are:

First number = 4

Second number = 0