Answer: [tex]9.38\times10^{33}[/tex]
Step-by-step explanation:
Given: Molecules in a liter of water = [tex]3.35\cdot10^{25}[/tex]
A certain river discharges about [tex]2.8\cdot10^8[/tex] liter of water every second.
Molecules in river = [tex]3.35\cdot10^{25}\times2.8\cdot10^8[/tex]
[tex]=3.35\cdot2.8\cdot10^{25}\cdot10^8\\\\= 9.38\times10^{25+8}\ \ \ \ [a^m\cdot a^n=a^{m+n}]\\\\= 9.38\times10^{33}[/tex]
Hence, there are [tex]9.38\times10^{33}[/tex] does the molecules in river per second.
