Perimeter of ΔABC is 12.41 units.
From the picture attached,
- ΔABC is a right triangle
- m(AC) = 5 units
- m(∠C) = 90°
- m∠A = 22°
Since, cosθ = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex] and sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
For angle A,
Adjacent side = AC = 5 units
Opposite side = BC
and Hypotenuse = AB
By substituting the values in the cosine ratio,
cos(22°) = [tex]\frac{5}{AB}[/tex]
AB = [tex]\frac{5}{\text{cos}(22^{\circ})}[/tex]
= 5.39
Since, sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
sin(22°) = [tex]\frac{BC}{5.39}[/tex]
BC = 5.39[sin(22°)]
= 2.02
Since perimeter of the given triangle ABC = AB + BC + AC
By substituting the measures of all sides in the expression of the perimeter,
Perimeter = 5.39 + 2.02 + 5
= 12.41 units.
Therefore, perimeter of the given triangle is 12.41 units.
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