Respuesta :

Space

Answer:

F. [tex]x=\frac{5}{2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: [tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Step-by-step explanation:

Step 1: Define

[tex]x^2 - 5x + \frac{25}{4} = 0[/tex]

Step 2: Identify Variables

[tex]a = 1\\b = -5\\c = \frac{25}{4}[/tex]

Step 3: Find roots

  1. Substitute [QF]:                    [tex]x=\frac{5\pm\sqrt{(-5)^2-4(1)(\frac{25}{4} )} }{2(1)}[/tex]
  2. Exponent:                             [tex]x=\frac{5\pm\sqrt{25-4(1)(\frac{25}{4} )} }{2(1)}[/tex]
  3. Multiply:                                [tex]x=\frac{5\pm\sqrt{25-25} }{2}[/tex]
  4. Subtract:                               [tex]x=\frac{5\pm\sqrt{0} }{2}[/tex]
  5. Evaluate:                               [tex]x=\frac{5}{2}[/tex]
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