Answer:
The final temperature is 31.95° C.
Explanation:
Given that,
Initial temperature of a sample of chloroform, [tex]T_i=25^{\circ} C[/tex]
Mass of chloroform, m = 150 g
It absorbs 1 kJ of heat, Q = 10³ J
The specific heat of chloroform, c = 00.96 J/gºC
We need to find the final temperature. The heat absorbed by an object in terms of specific heat is given by :
[tex]Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\\dfrac{Q}{mc}+T_i=T_f\\\\T_f=\dfrac{10^3}{150\times 0.96}+25\\\\=31.95^{\circ} C[/tex]
So, the final temperature is 31.95° C.