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A 40.0-kg package on a the roller belt conveyor is moving at 0.600 m/s. What is
its kinetic energy? *
O 7.2 J
O 12 J
O 14.4 J
O 0J
O24J

Respuesta :

Answer:

7.2 J

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 40 \times {0.6}^{2} \\ = 20 \times 0.36 \\ = 7.2[/tex]

We have the final answer as

7.2 J

Hope this helps you

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