Question

The equation of trajectory of a projectile is y=10x−[95​]x2,(m). The maximum height is reached when x is

A

36m

B

24m

C

18m

D

9m

Answer 1

Answer:

Step-by-step explanation:

For maximum height:

dxdy​=0⇒dxd​(10x−95​x2)=0

⇒10−910​x=0

⇒x=9 m

Hope it helps beza