Respuesta :

Answer:

[tex]5\ units[/tex]

Step-by-step explanation:

[tex]From\ the\ graph,\\Coordinates\ of\ Point\ P=x_1,y_1=-10,15\\Coordinates\ of\ Point\ T=x_2,y_2=15,15\\Hence,\\As\ we\ know\ that,\\Linear\ Distance(d)\ between\ any\ two\ points\ on\ the\ cartesian\ plane\\ is\ given\ by:\\d=\sqrt{(x_2-x_1)+(y_2-y_1)} \\Hence, here\\Distance\ between\ Points\ P\ and\ T=\sqrt{(15-(-10))+(15-15)\\[/tex]

[tex]Distance\ between\ Points\ P\ and\ T=\sqrt{(15+10)}\\Distance\ between\ Points\ P\ and\ T=\sqrt{25}\\ Hence,\\Distance\ between\ Points\ P\ and\ T=5\ units[/tex]

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