Answer:
6.18 m/s
Explanation:
Given that a ferry approaches shore, moving north with a speed of 6.1 m/s relative to the dock. A person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.0 m/s relative to the ferry Part. What is the speed of the person relative to the dock?
The speed of the person can be calculated by using pythagorean theorem.
Let the speed of the person = S
S^2 = 6.1^2 + 1^2
S^2 = 38.21
S = sqrt ( 38.21)
S = 6.18 m/s
Therefore, the speed of the person relative to the dock is 6.18 m/s
