Answer:
see explanation
Step-by-step explanation:
(1)
The distance walked ( arc length ) is calculated as
arc = circumference of circle × fraction of circle
= 2πr × [tex]\frac{210}{360}[/tex]
= 2π × 45 × [tex]\frac{21}{36}[/tex]
= 90π × [tex]\frac{7}{12}[/tex]
≈ 165 ft ( to the nearest foot )
(2)
The area (A) covered is calculated as
A = area of circle × fraction of circle
= πr² × [tex]\frac{122}{360}[/tex]
= π × 18² × [tex]\frac{61}{180}[/tex]
= 324π × [tex]\frac{61}{180}[/tex]
≈ 345 in² ( to the nearest square inch )
(3)
The area (A) is calculated as
A = area of circle × fraction of circle
= πr² × [tex]\frac{80}{360}[/tex] ( r is the distance shot by sprinkler )
= π × 75² × [tex]\frac{8}{36}[/tex]
= 5625π × [tex]\frac{2}{9}[/tex]
≈ 3927 ft² ( to the nearest square foot )
Answer:
9514 1404 393
Answer:
top down: 1, 5, 6, 4, 8, 2, 3, 7
Step-by-step explanation:
It appears the expected order may be ...
__
Write the formula for the arc length of a circle with central angle, θ, in degrees.
\textit{Arc Length}=\dfrac{\theta}{360^{\circ}}\cdot 2\pi rArc Length=
360
∘
θ
⋅2πr
Replace 360° with 2π radians.
\dfrac{\theta}{360^{\circ}}=\dfrac{\theta}{2\pi}
360
∘
θ
=
2π
θ
Replace the angle ratio in degrees with the angle ratio in radians.
\textit{Arc Length}=\dfrac{\theta}{2\pi}\cdot 2\pi rArc Length=
2π
θ
⋅2πr
Simplify by cancelling
\textit{Arc Length}=\theta rArc Length=θr
