Question

how fast must a 1000 kg car be moving to have a kinetic energy of 2.0×10^5j​

Answer 1

Answer:

E=0.5 m v^2

2*10^-5 = 0.5 1000*v^2

4*10^-5=1000v^2

4*10^-8=v^2

2*10^-4 =v

Answer 2

Answer:

20m/s

Explanation:

Ek=1/2(m)(v)^2

Ek=2.0x10^5

m=1000kg

v=?

2.0x10^5=1/2(1000)v^2

(2.0x10^5)/(0.5x1000)=v^2

$\sqrt{400}$=v

20m/s=v