Question

The first side of a triangle is scm long.
The second side is twice as long as the first.
The third side is 5 cm longer than the second side.
a The perimeter of the triangle is 1 metre.
Write an equation to show this.
b Solve the equation.
c Find the length of the longest side of the triangle.​

Answer 1

Answer:

First side is 19, second side is 38 and third side, the longest is 43.

Step-by-step explanation:

Let's call the first side a.  

The second side, being twice as long as the first, is 2a.

The third side is 2a+5.

The equation is:

a+2a+2a+5=100, since 1 metre is 100 centimetre.

5a+5=100

5a=95

a=19

First side is 19, second side is 38 and third side, the longest is 43.

Answer 2

An equation is formed of two equal expressions. The length of the longest side of the triangle is 43 cm.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given to us that the first side of a triangle is x cm long, The second side is twice as long as the first, The third side is 5 cm longer than the second side and The perimeter of the triangle is 1 metre. Therefore,

• The length of the first side will be x cms.
• The length of the second side will be twice x, 2x.
• The third side is 5 cm longer than the second side, 2x+5.

Since the perimeter of the triangle is 1 meter which is equal to 100 cm. And the perimeter is the sum of all the sides of a triangle. The perimeter can be written as,

$x+(2x)+(2x+5) = 100\\\\x+2x+2x+5=100\\\\5x+5=100\\\\5x=95\\\\x=19$

Thus, the value of x is 19.

A.)  The equation that represents this condition is x+2x+2x+5=100.

B.) The length of the longest side of the triangle is 2x+5, where the value of x is 19. Therefore, the length of the longest side can be written as,

$\text{Length of the third side} =2x+5 =2(19)+5=38+5=43\rm\ cms$

Thus, the length of the longest side of the triangle is 43 cm.

Learn more about Equation:

https://brainly.com/question/2263981