Answer:
x = 4 or -3
Step-by-step explanation:
[tex]\sqrt{x+12}[/tex] = x
To get rid of the square root, we need to square both sides.
x + 12 = x²
Get all variables/ integer on to one side.
0 = x² - x - 12
Use any method to solve this quadratic equation. I'm going to use the completing the square method.
12 = x² - x
12 + 0.25 = x² - x + 0.25
[tex]\sqrt{12.25}[/tex] = [tex]\sqrt{(x - 0.5)^2}[/tex]
±3.5 = x - 0.5
x = 0.5 ± 3.5
x = 4 or -3
