Answer:
1)49m/s
2)122.5m
Explanation:
The expression below can be use to calculate the initial velocity from law of motion
V2 - V1= at
Where V2= final velocity
V1= initial velocity( from rest)
a=acceleration
t= time= 5 seconds
But V2=0
V1=gt
Where g= acceleration due to gravity= 9.8m/s^2
V1= 9.8×5
V1=49m/s
Then we can now calculate the maximum height the rocket reaches by using below formula
V^2=2gh
h(max)=v^2/2g
Where h= maximum height
V2= initial velocity
=49^2/(2×9.8)
=2401/19.6
=122.5m
Hence the maximum height it reaches vis 122.5m
