Question

What is the equation of the line that passes through the point (-5, 7) and has a slope of -2/5?​

Answer 1

Answer:

I hope that it will be help full for u

Step-by-step explanation:

As we know the equation of line is ,

y= mx+ c

As given

slope=m=-2/5

also given (x, y)= (-5, 7)

we get   x=-5  , y=7

putt in the equation of line all these values we get ,

7=(-2/5)(-5) +c

c=7-2

c=5   now putt the value of c and m  in equation of line we will get ,required equation of line

y = (-2/5)x + 5  Ans

Answer 2

Using slope intercept form, the equation of the line that passes through the point (-5,7) and has a slope of -2/5 is y = - 2/5x + 5.

What is slope intercept form?

The equation of the "straight line is in the form y = mx + b where 'm' is the slope of the line, 'b' is the y - intercept form" is called slope intercept form.

According to the question,

The line passes through the point (-5,7) and has slope of -2/5,

The equation of the straight line y = m x + c. Substitute (-5,7) and slope -2/5 in general equation we have 7 = -2/5 (-5) + c

7 = 2 + c

c = 7-2

c = 5

Hence, using slope intercept form, the equation of the line that passes through the point (-5,7) and has a slope of -2/5 is y = - 2/5x + 5.

Learn more about slope intercept form here

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