Question

15 point hurry
In the following function defined by an equation in the form y = a x squared + b x + c, identify the values of a, b, and c.
y = two-thirds x squared + 3
a.
a = 0, b = two-thirds, c = 3
b.
a = two-thirds, b = 0, c = 3
c.
a = 0, b = 3, c = two-thirds
d.
a = two-thirds, b = two-thirds, c = 3

Answer 1

Given:

$y=\dfrac{2}{3}x^2+3$

This equation is in the form $y=ax^2+bx+c$.

To find:

The values of a, b and c.

Solution:

We have,

$y=\dfrac{2}{3}x^2+3$

It can be written as

$y=\dfrac{2}{3}x^2+(0)b+3$

On comparing this equation with $y=ax^2+bx+c$, we get

$a=\dfrac{2}{3},b=0,c=3$

Therefore, the correct option is b.