Answer:
648.7g of Mg must be added
Explanation:
Based on the reaction:
3Mg + 1/2P4 → Mg3P2
3 moles of Mg produce 1 mole of Mg3P2
To solve this problem we neeed to find the moles of Mg3P2 in 1200g. With these moles and the chemical reaction we can finf moles of Mg and its mass:
Moles Mg3P2 -Molar mass: 134.88g/mol-:
1200.0g Mg3P2 * (1mol / 134.88g) = 8.897 moles of Mg3P2
Moles Mg:
8.897 moles of Mg3P2 * (3mol Mg / 1mol Mg3P2) = 26.69 moles of Mg
Mass Mg -Molar mass: 24.305g/mol-:
26.69 moles of Mg * (24.305g / 1mol) =
