Question

In circle R with mZQRS = 74 and QR = 17 units find area of sector QRS. Round
to the nearest hundredth.

Answer 1

Answer:

$A=186.70\ \text{unit}^2$

Explanation:

Given that,

$\angle QRS = 74^{\circ}\\\\QR = 17\ \text{units}$

We need to find the area of sector QRS. The formula for the area of a sector is given by :

$A=\dfrac{\theta}{360}\times \pi r^2$

QR = RS = r = 17 units

So,

$A=\dfrac{74}{360}\times \dfrac{22}{7}\times (17)^2\\\\=186.70\ \text{unit}^2$

So, the area of sector QRS is $186.70\ \text{unit}^2$