Respuesta :
Answer:
None of the options match
Step-by-step explanation:
First let's check option 1: lines 2 and 3.
line 2 in mx+b form: y=-1/16x -5
line 3, already in mx+b form: y=-6x-7
if it was perpendicular, the slopes should have been -1/16 and 16 or -6 and 1/6.
now for the 2nd option: lines 1 and 2.
line 1 in mx+b form: y=-8x-5
line 2 in mx+b form: y=-1/16x-5
Again, the slopes do not match, they should have been -8 and 1/8 or -1/16 and 16.
For the 3rd option: all lines
this is obviously wrong since lines 1, 2 and 2, 3 are not perpendicular themselves. No need to bother checking this option.
Lastly, 1 and 4.
line 1 in mx+b form: y=-8x-5
line 4 --> y+3=18x-18 --> y=18x-21
This is also wrong since the slopes should have been -8 and 1/8 or 18 and -1/18.
To conclude, I think the answer is none. None of the combinations on here are perpendicular anyways...
Answer:
D
Step-by-step explanation:
We have the four lines:
[tex]\displaystyle\text{Line 1: }y+8x&=-5 \\\\ \text{Line 2: } x+\frac{1}{6}y&=-5\\\\\text{Line 3: } y&=-6x-7 \\\\\text{Line 4: } y+3&=\frac{1}{8}(x-1)[/tex]
Remember that for two lines to be perpendicular, their slopes are negative reciprocals of each other.
So, let’s determine the slope of each line.
For Line 1, we can rewrite our equation as:
[tex]y=-8x-5[/tex]
So, the slope of Line 1 is -8.
We can rewrite Line 2 as:
[tex]\displaystyle \begin{aligned} \frac{1}{6}y&=-x-5\\y&=-6x-30\end{aligned}[/tex]
So, the slope of Line 2 is -6.
The slope of Line 3 is also -6.
And the slope of Line 4 is 1/8.
So, the slopes of perpendicular lines must be negative reciprocals.
The negative reciprocal of -8 (slope of Line 1) is 1/8. We multiply by a negative and then take the reciprocal.
Since the slope of Line 4 is 1/8, this means that Lines 1 and 4 are perpendicular.
For Lines 2 and 3, they have the same slope, not negative reciprocals of each other.
So, they will instead of parallel instead of perpendicular.
And Line 1 is perpendicular only to Line 4, and no other line.
Therefore, our answer is D.