Question

A dog sits 1.50m from the center of the merry-go-around and revolves at a tangential speed of 1.80m\s. If the dog’s mass is 18.5kg, what is the magnitude of the centripetal force on the dog?


A) 25.53n
B) 32.51n
C) 39.96n
D) 42.55n

Answer 1

Answer:

39.96 N

Further explanation:

Given

radius=R=1.5 m

Tangential speed =v=1.80m\s

mass of the dog=18.5 kg

Required

The magnitude of the centripetal force

Analysis

Use Centripetal force formula :

$]\large{\boxed{\bold{F= \frac{mv^2}{R}}}$

F = centripetal force , N  

m = mass , Kg  

v = linear velocity/tangential  , m/s  

r = radius , m  

Solution

$\tt F=\dfrac{18.5\times 1.8^2}{1.5}\\\\F=39.96~N$

Paraphrase

The magnitude of the centripetal force on the dog : 39.96 N