Question

How many grams of hydrogen fluoride is required to react with 70 grams of tin?

Answer 1

Answer: 5.0 g of hydrogen

Explanation:

Sn

l

+

2HF

→

SnF

2

+

H

2

Moles of H

2

=

2.5

mol Sn

×

1 mol H

2

1

mol Sn

=

2.5 mol H

2

Mass of H

2

=

2.5

mol H

2

×

2.016 g H

2

1

mol H

2

=

5.0 g H

2