Respuesta :
Answer:
I answered Number 4 (Solids and Elasticity)
Explanation:
Part a)
If a weight of 10 N stretches a certain spring 3 cm, a) Determine the spring constant k.
Solution:
To determine the spring constant we use the formula F = k x (X)
where ,
F is the force applied in this case 10 N
x is the displacement of the spring’s end from its equilibrium position in this case 3 cm
[tex]F=kx\\10=k(3)\\10/3=k\\k=3.33\ N/cm[/tex]
Part b)
b) Determine how much stretch will occur if you double the weight with a force of 20 N?
Solution:
If we double the weight to 20 N we need to find the need to find the new stretch of the spring which is x. But we know the spring constant which is k so it becomes,
[tex]F=kx\\20=3.33x\\20/3.33=x\\x=6.00\ cm[/tex]
So we can see that if we double the Force the stretch is also doubled thus showing us a direct variation as seen in the formula F = k x (X)
Part c)
c) Using g=9.8 m/s^2 determine the mass of the 10 N weight and round your answer to 3 significant digits.
Solution:
The formula of weight is,
[tex]W=mg[/tex]
where,
w is the weight of the object in Newtons (N) which is 10 in this case
m is the mass of the object in kilograms (kg) we to need to find in this case and,
g is acceleration due to gravity which is constant 9.8 m/s^2
so now,
[tex]W=mg\\10=m(9.8)\\10/9.8=m\\m=1.02\ kg[/tex]