Question

A rock is thrown straight up from the surface of the Earth. Which one of the following statements describes the energy
transformation of the rock as it rises? Neglect air resistance.
a) The total energy of the rock increases.
b) The kinetic energy increases and the potential energy decreases.
c) Both the kinetic energy and the potential energy of the rock remain the same.
d) The kinetic energy decreases and the potential energy increases.
e) Both the potential energy and the total energy of the rock increase.

Answer 1

Answer: d

Explanation:

Uuhhh I’m not good at explanations...

Answer 2

The kinetic energy decreases while the potential energy increases.

Option d is the answer because as soon as this ball gets thrown from the surface of the earth kinetic energy would be at its greatest.

we have

$k=\frac{1}{2} mv^{2}$

The velocity is going to be minimized. As the ball is going up its velocity would be falling or decreasing due to gravity. $k=\frac{1}{2} mv^{2}$ would then have a smaller value. So kinetic energy is reducing/decreasing.

We have potential energy as u = m*g*h = 0. This is because the height is 0 as the ball is released. But as the ball goes up, the height would start to increase so the potential energy increases.

In conclusion as the ball is thrown straight from the earth, kinetic energy decreases and potential energy increases.

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