Question

Which graph represents the equation y = – (x – 1)2 + 1?

On a coordinate plane, a parabola opens up. It goes through (0, 2), has a vertex at (1, 1), and goes through (2, 2).
On a coordinate plane, a parabola opens down. It goes through (0, 0), has a vertex at (1, 1), and goes through (2, 0).
On a coordinate plane, a parabola opens down. It goes through (negative 2, 0), has a vertex at (negative 1, 1), and goes through (0, 0).
On a coordinate plane, a parabola opens up. It goes through (negative 2, 2), has a vertex at (negative 1, 1), and goes through (0, 2).

Answer 1

Answer:

for y = - (x-1)^2 + 1 its B the second graph

Step-by-step explanation:

find the vertex

y = -x^2 + 2x

its (1,1)

and x is negative so it must be that one.

Answer 2

On the coordinate plane, the parabola opens down, it goes through (0, 0), has a vertex at (1, 1), and goes through (2, 0).

What is a parabola?

A parabola is a U-shaped plane curve where any point is at an equal distance from a fixed point and from a fixed straight line.

According to the given problem,

y = - ( x - 1 )² + 1 is in the form of y = ( x - h )² + k where, (h , k) is the vertex of the parabola which is ( 1 , 1) as h = 1

                                                       k = 1

Now, after plotting the graph we can find out that the parabola passes through ( 2 , 0 ) and the minus sign indicates a parabola that opens down.

Hence, the parabola has a vertex at (1 , 1), goes through (0 , 0) and (2 , 0).

Learn more about parabola here:

https://brainly.com/question/4074088

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