Respuesta :
3x^2 - 7x + 12 = 0 ....subtract 12 from both sides
3x^2 - 7x = -12 ....divide both sides by 3 to get x^2 by itself
x^2 - 7/3x = -4
His work is not accurate because he divided the second term by 4 instead of 3.
3x^2 - 7x = -12 ....divide both sides by 3 to get x^2 by itself
x^2 - 7/3x = -4
His work is not accurate because he divided the second term by 4 instead of 3.
Answer:
His work is not accurate.
Step-by-step explanation:
Since, when we solve a quadratic equation by completing the square method,
Then, we follow the following steps,
Step 1 : Move the constant term to the right side of the equation,
Step 2 : Make 1 as the coefficient of [tex]x^2[/tex]
Step 3 : Add the square of the half of the coefficient of the x in both sides.
Here, the given equation is,
[tex]3x^2-7x+12=0[/tex]
Step 1 : [tex]3x^2-7x=-12[/tex]
Step 2 : [tex]x^2-\frac{7}{3}x=-4[/tex]
Since, in the Joseph's work the above expression is [tex]x^2-\frac{7}{4}x=-4[/tex]
Hence, his work is not accurate because he divide the second term of the left side of equation by 4 instead of 3.