Answer:
x^3−2x2+4x+3=x2−5x+15+−41x+3
Step-by-step explanation:
1.Divide the leading term of the dividend by the leading term of the divisor: x3x=x2.
Write down the calculated result in the upper part of the table.
Multiply it by the divisor: x2(x+3)=x3+3x2.
Subtract the dividend from the obtained result: (x3−2x2+4)−(x3+3x2)=−5x2+4.
2.Divide the leading term of the obtained remainder by the leading term of the divisor: −5x2x=−5x.
Write down the calculated result in the upper part of the table.
Multiply it by the divisor: −5x(x+3)=−5x2−15x.
Subtract the remainder from the obtained result: (−5x2+4)−(−5x2−15x)=15x
3.Divide the leading term of the obtained remainder by the leading term of the divisor: 15xx=15.
Write down the calculated result in the upper part of the table.
Multiply it by the divisor: 15(x+3)=15x+45.
Subtract the remainder from the obtained result: (15x+4)−(15x+45)=−41.
