Question

A ball is thrown 24 m/s into the air. How high does it go?

Answer 1

Vi = 24
Vf = 0
A = 9.81 m/s ^2
D = ? m

Vf^2 = Vi^2 + 2ad
0 = (24)^2 + 2(-9.81)(d)
0 = 576 + (-19.62d)
-576 = -19.62d
-576/-19.62 = -19.62d/-19.62

D = 29.35 m.

I believe this would be the solution.

Answer 2

We have that for the Question "A ball is thrown 24 m/s into the air. How high does it go?" it can be said that how high the ball goes is

s=29.387m

From the question we are told

A ball is thrown 24 m/s into the air. How high does it go?

Generally the Newtons equation for the  Motion  is mathematically given as

$v^2=2as\\\\Therefore\\\\(24)^2=2*(9.8)*s\\\\s=\frac{(24)^2}{2(9.8)}\\\\s=29.387m$

Therefore

How high the ball goes is

s=29.387m

For more information on this visit

https://brainly.com/question/23379286