Write an equation of the line below
![Write an equation of the line below class=](https://us-static.z-dn.net/files/dba/a47ba359059ceac9a98ee270f613c88b.png)
Answer:
The equation of the line is:
[tex]y = 4x + 3[/tex]
Step-by-step explanation:
We know that the slope-intercept of line equation is
[tex]y = mx+b[/tex]
Where m is the slope and b is the y-intercept
Given the two points on a line
Finding the slope between (0, 3) and (-2, -5)
[tex]\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\left(x_1,\:y_1\right)=\left(0,\:3\right),\:\left(x_2,\:y_2\right)=\left(-2,\:-5\right)[/tex]
[tex]m=\frac{-5-3}{-2-0}[/tex]
[tex]m=4[/tex]
We know that the y-intercept can be computed by setting x=0 and determining the corresponding y-value.
From the graph, it is clear:
at x = 0, y = 3
Thus, y-intercept = b = 3
Substituting m = 4 and b = 3 in the slope-intercept form of line equation
[tex]y = mx+b[/tex]
[tex]y = 4x + 3[/tex]
Therefore, the equation of the line is:
[tex]y = 4x + 3[/tex]