Question

Which is the equation of a line that has a slope of -5 and passes through point (-3,-1)? O y=-3x+1 O y=-3x+3 O y=-x-1 O y=-x-3 3​

Answer 1

Note: Your answer choices are not clear, thus I have solved the complete question which anyways should be able to clear your concept.

Answer:

The equation of a line that has a slope of -5 and passes through the point (-3,-1) will be:

• y = -5x - 16

Step-by-step explanation:

Given

• slope = m = -5

• point = (-3, -1)

We know that the slope-intercept form of the line equation is

$y=mx+b$

Here:

• m is the slope

• b is the y-intercept

Now, substituting m = -5 and (-3, -1) in the slope-intercept form of the line equation  to determine the y-intercept 'b'

$y=mx+b$

-1 = -5(-3) + b

switch sides

-5(-3) + b = -1

15 + b = -1

b = -1 - 15

b = -16

Now, substituting m = -5 and b = -16 in the slope-intercept form of the line equation  to determine the equation of a line

$y=mx+b$

y = -5x + (-16)

y = -5x - 16

Therefore, the equation of a line that has a slope of -5 and passes through the point (-3,-1) will be:

• y = -5x - 16

Note: Your answer choices are not clear, thus I have solved the complete question which anyways should be able to clear your concept.