Answer:
0.9545
Step-by-step explanation:
Given that :
Mean (m) = 120
Standard deviation (s) = 12
what percentage of values is within the interval 96 to 144
P(96 < x < 144)
P(x < 96)
obtain the standardized score (Z) :
Z = (x - m) / s
Z = (96 - 120) / 12 = - 2
p(Z < - 2) = 0.02275 ( Z probability calculator)
P(x < 144)
obtain the standardized score (Z) :
Z = (x - m) / s
Z = (144 - 120) / 12 = 2
p(Z < - 2) = 0.97725 ( Z probability calculator)
p(Z < - 2) - p(Z < 2) = 0.97725 - 0.02275 = 0.9545
