Answer: For This Specific Question it is B, But there is a question very similar that doesn't have the pi's in the equation and the answer to that one is A.
Step-by-step explanation: Very sorry if this is confusing :)
Pythagorean identities are three basic identities for trigonometric ratios. The equation that is of the form [tex]\sin^2(\pi) + \cos^2(\pi) =1[/tex] is given by: Option B: [tex]0^2 + (-1)^2 = 1[/tex]
Equations which shows that the Pythagorean identities are true will be verifying them for some specific angles. For that we need to know about Pythagorean identities.
[tex]sin^2(\theta) + cos^2(\theta) = 1\\\\1 + tan^2(\theta) = sec^2(\theta)\\\\1 + cot^2(\theta) = csc^2(\theta)[/tex]
Using the first Pythagorean Identity to get one of its special case
For angle being [tex]\pi[/tex] radians(or equal to 180 degrees), we have:
[tex]sin(\pi) = 0\\cos(\pi) = -1[/tex]
Thus, for the first Pythagorean identity at angle [tex]\pi[/tex] radians, we get:
[tex]sin^2(\pi) + cos^2(\pi) = 1\\\\0^2 + (-1)^2 = 1[/tex]
Thus, the equation that is of the form [tex]\sin^2(\pi) + \cos^2(\pi) =1[/tex] is given by: Option B: [tex]0^2 + (-1)^2 = 1[/tex]
Learn more about Pythagorean identities here:
https://brainly.com/question/24287773
