Answer:
Since the calculated value of t= 2.8782 does not fall in the critical region so we accept H0 and may conclude that the drug is not effective in increasing sleep.
Step-by-step explanation:
d d²
1.0, 1
0.8, 0.64
1.1, 1.21
0.1, 0.01
- 0.1, 0.01
4.4, 19.36
1.5, 2.25
1.6, 2.56
4.6, 21.16
3.4 11.56
∑18.4 ∑59.76
1: We state our null hypothesis as
H0 : μd= 0 against the claim Ha: μd ≠ 0
2: The significance level is set at ∝ = 0.01
3: The test statistic under H0 is
t= d`/ sd /√n
4:The critical region is t ≥ t ( 0.005) 9 = 3.250
5:Computation:
d`= ∑d/n= 18.4/10= 1.84
Sd² = ∑(di- d`)²/n-1 = 1/n-1 [∑di²- (∑di)² /n]
= 1/9 [59.76 - (18.4)²/10]
=(59.76 - 33.856)/9
= 25.904/9
= 2.8782
6: Conclusion:
Since the calculated value of t= 2.8782 does not fall in the critical region so we accept H0 and may conclude that the drug is not effective in increasing sleep.
This is because we have taken H0 as the mean of the difference is zero.
This can only be zero when the drug is not effective.