Answer:
The speed with which the man flies after hitting the rock is 5.5 m/s
Explanation:
The given parameters are;
The mass of the man, m₁ = 100 kg
The mass of the scooter, m₂ = 10 kg
The initial speed of the man and the scooter, v₁ = 5 m/s
The speed with which the man flies after hitting the rock = v₂
The final speed of the scooter, v₃ = 0 m/s
The momentum = Mass × Velocity and by the principle of conservation of momentum, we have;
The total initial momentum = The total final momentum
The total initial momentum = (m₁ + m₂) × v₁ = (100 + 10) × 5 = 550
The total initial momentum = 550 kg·m/s
The total final momentum = m₁ × v₂ + m₂ × v₃, which gives;
The total final momentum = 100 × v₂ + 10 × 0
By conservation of momentum, the total initial momentum = The total final momentum, we get;
550 = 100 × v₂ + 10 × 0
∴ 550 = 100 × v₂
v₂ = 550 kg·m/s/(100 kg) = 5.5 m/s
The speed with which the man flies after hitting the rock = v₂ = 5.5 m/s
