Find the solution for this system of equations.
2x − 3y = 2
x = 6y − 5

solve for both X and Y

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Answer:

x = 3, y = 1[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

2x - 3y = 2 --- Equation 1

x = 6y - 5 --- Equation 2

Subsitute x = 6y - 5 into Equation 1:

2x - 3y = 2

2(6y - 5) - 3y = 2

Expand the brackets.

12y - 10 - 3y = 2

Evaluate like terms.

9y - 10 = 2

Isolate 9y.

9y = 2 + 10

    = 12

Find y.

y = 12 ÷ 9

y = 1[tex]\frac{3}{9}[/tex]

y = 1[tex]\frac{1}{3}[/tex]

Substitute y = 1[tex]\frac{1}{3}[/tex] into Equation 2:

x = 6y - 5

x = 6(1[tex]\frac{1}{3}[/tex]) - 5

  = 8 - 5

x = 3

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