solve using method of intervals. please show step/explain. thank you

Answer:
x ≤ 3
Step-by-step explanation:
[tex]\frac{x-3}{x+4}[/tex] ≤ 0
Multiply both sides by (x+4) so that both sides do not have any fractions.
x - 3 ≤ 0 × (x+4)
Remember that anything multiplied by 0 becomes 0.
x - 3 ≤ 0
Add both sides by 3 so that there is only x on the left side. (x - 3 + 3 = x)
x ≤ 0 + 3
x ≤ 3