the picture. and answer 1-6. please hurry
![the picture and answer 16 please hurry class=](https://us-static.z-dn.net/files/d58/bd25565a58e2784d582ed502b0b4e559.png)
Answer:
Step-by-step explanation:
From the figure attached,
1). Sin(D) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{EF}{DF}[/tex]
= [tex]\frac{24}{26}[/tex]
= [tex]\frac{12}{13}[/tex]
2). Cos(D) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{ED}{DF}[/tex]
= [tex]\frac{10}{26}[/tex]
= [tex]\frac{5}{13}[/tex]
3). tan(D) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{EF}{DE}[/tex]
= [tex]\frac{24}{10}[/tex]
= [tex]\frac{12}{5}[/tex]
4). sin(F) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{DE}{DF}[/tex]
= [tex]\frac{10}{26}[/tex]
= [tex]\frac{5}{13}[/tex]
5). cos(F) = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
= [tex]\frac{EF}{DF}[/tex]
= [tex]\frac{24}{26}[/tex]
= [tex]\frac{12}{13}[/tex]
6). tan(F) = [tex]\frac{\text{Adjacent side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{DE}{EF}[/tex]
= [tex]\frac{10}{24}[/tex]
= [tex]\frac{5}{12}[/tex]